Guru
Joined: 24/12/2017
Location: AustraliaPosts: 1619
| Posted: 06:47am 26 Apr 2020 |
Hi again Tom,
It took more than a couple of coffees but I think I have it worked out.
b=0 represents the 3 values of (x-1,y-1) , (x-1,y) and (x-1,y+1) which are off the edge and are zero according to the rules.
c is same but around x and
d is the same around x+1
Adj includes the value of the current cell which you take into account when updating the new matrix.
And then you maintain that moving window of 9 cells as you move along x.
b=c
c=d
And you only need to calculate d each time around the loop.
Is that correct?
For a printing version the screen update could be quicker if instead of a$ being used to print one line, an array a$(x,y) could hold the whole screen which could be printed in a FOR NEXT loop?
Bill
Keep safe. Live long and prosper.