Guru
Joined: 11/02/2018
Location: AustraliaPosts: 3348
| Posted: 11:39am 28 Sep 2022 |
Volhout said:
" For this diode to work, it should be a shottky diode. And these tend to have high leakage (1uA). "
Could that leakage be the problem?
Temporarily remove it, leave the input open circuit then measure the voltage on the pin in all conditions.
If that is it then some other protection measure will be needed.
Edit
Ignore that I missed the post where you found the problem.
Edited 2022-09-28 21:57 by phil99