Newbie
Joined: 07/10/2005
Location: AustraliaPosts: 34
| Posted: 07:20am 11 Oct 2005 |
Hmmmmm
Yeah thats kinda what I figured, with 1:3 ratio = triple your voltage, as voltage is proportional to RPM (kv).
As far as I understand gear/belt systems, the same power in comes out, minus a few percent for inefficiencies, maybe 5 to 10%(?).
So if:
1x turbine shaft torque * 500 RPM = 500thingamies(!), then
0.333x motor shaft torque * 1500 RPM = 500thingamies too.
Minus a few thingamies for inefficiency.
I think this might just work.
A bonus of this might be that the motor is shifted closer to its peak efficiency range.
Ok, I'ma hava go at this.
BTW, that should read 'high kv' in my previous post.