Shifting numbers in MMBasic

Author	Message
BobD Guru Joined: 07/12/2011 Location: Australia Posts: 935	Posted: 04:15am 08 Mar 2012       x=(byte1*(2^16) + byte2*(2^8) + byte3) \ 2^(8-y) I had a bit of uncertainty about the 8-y. Not sure what you wanted. I assumed right shift by 8-y.Edited by BobD 2012-03-09