Senior Member
Joined: 11/07/2011
Location: AustraliaPosts: 164
| Posted: 04:19am 08 Mar 2012 |
In a word - yes.
I don't have the time for a full code example now, but essentially to LeftShift (<<) by 16 or 8 bytes, do this:
byte1 = (byte1 * (2 ^ 16)) And &hFFFF
byte2 = (byte2 * (2 ^ 8)) And &hFF
x = byte1 + byte2 + byte3
Then RightShift(>>) by 8-y bytes is:
x = x \ (2 ^ (8 - y))
Cheers,
crackerjack