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Forum Index : Microcontroller and PC projects : bit swap in byte

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twofingers
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Joined: 02/06/2014
Location: Germany
Posts: 1102
Posted: 06:28pm 27 Jul 2022
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  matherp said  Just do it on each byte in turn and then swap the bytes end to end

Again: your solution is elegant.

I think we will lost the speed advantage if we do the operation 8 times.
8 * 15us would be 120us (or more) vs. 30us for the CSub solution.

Kind regards
Michael

EDIT:
Anyway a good solution for Gerald!
Edited 2022-07-28 04:30 by twofingers
 
ville56
Regular Member

Joined: 08/06/2022
Location: Austria
Posts: 67
Posted: 06:56pm 27 Jul 2022
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indeed it is refreshing for my mind to see all the different solutions. It leads me away from my old and small paths of thinking for this particular problem. This forum is really world class with all its potential.

@twofingers: thanks for the cookbook to csub :-), i really appreciate it. Have to dive into it deeper, but at the moment i have to spend some time on servicing my motorbike for my annual statutorial inspection.

Regards and thanks,
Gerald
                                                                 
73 de OE1HGA, Gerald
 
twofingers
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Joined: 02/06/2014
Location: Germany
Posts: 1102
Posted: 06:58pm 27 Jul 2022
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@Gerald
Viel Glück beim TÜV!
 
ville56
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Joined: 08/06/2022
Location: Austria
Posts: 67
Posted: 07:45pm 27 Jul 2022
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Danke!
                                                                 
73 de OE1HGA, Gerald
 
twofingers
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Joined: 02/06/2014
Location: Germany
Posts: 1102
Posted: 11:43am 28 Jul 2022
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Just to complete this topic. A version for 8-bits reversing:

8Bitorderreverse.zip

On a 378MHz PicoMite reversing the bit order for a Byte takes 12us.

Regards
Michael

edit:
Just to clarify: I think Peter's solution is the better one.
Edited 2022-07-28 22:24 by twofingers
 
toml_12953
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Joined: 13/02/2015
Location: United States
Posts: 304
Posted: 03:05pm 28 Jul 2022
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Here's one way:

10 INPUT "Enter a number:",n:print
20 h$=right$("0000"+hex$(n),4)
30 PRINT h$
40 h$=right$(h$,2)+left$(h$,2)
50 nr=val("&h"+h$)
60 PRINT h$
70 PRINT nr
 
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